Question #cd757

1 Answer
Jane
Feb 22, 2018

When the object reaches the bottom of the inclined plane,its total energy is purely kinetic,considering horizontal to be the reference level.

And,the energy value is 1/2 ×0.25×5^2=3.125J (using 1/2mv^2)

Now,total energy on top of the inclined plane was purely potential energy as the object was at rest,and its value was mgh (where, h is the height of the plane)

As, h/l = sin 30 so, h=l/2=6/2=3m (l is the length of the inclined plane)

So,total energy at the beginning of the journey was 0.25×9.81×3=7.36 J

So,this decrease in total energy value suggests that it must have been utilized to overcome the frictional force,

And the value is (7.36 - 3.125)=4.24 J

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