Question #8380b

1 Answer
Stefan V.
Sep 13, 2016

#"1.07 g/cm"^3#

Explanation:

Here's a quick way of figuring out the density of the saline solution.

Notice that the problem provides you with the density of pure water at #4^@"C"#. Use this to find the volume of pure water that has a mass of #"11.3 g"# at that temperature

#11.3 color(red)(cancel(color(black)("g"))) * "1 cm"^3/(1.00color(red)(cancel(color(black)("g")))) = "11.3 cm"^3#

Since you know that an equal volume of saline solution has a mass of #"12.g"# at #4^@"C"#, you can say that its density, #rho_"sal"#, will be equal to

#rho_"sal" = "12.1 g"/"11.3 cm"^3 = color(green)(bar(ul(|color(white)(a/a)color(black)("1.07 g/cm"^3)color(white)(a/a)|)))#

The answer is rounded to three sig figs.

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