Question #920cd

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Question #920cd

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Answer 1 · 2016-09-12T07:35:36

The escape velocity is simply defined as the lowest speed which an object must have to be able to escape the gravitational field of a planet (or an object)

For a planet (or any spherical object) if mass $m$ $m$ , radius $r$ $r$ , the escape velocity is given by the relation,

$v = \sqrt{\frac{2 m G}{r}}$ $v = sqrt((2mG)/r)$

For the earth, the escape velocity is about 11.2 km/s.

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Question #920cd

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