Question #72a0e
1 Answer
Sep 12, 2016
- Initial velocity
=u_1
Accelerationa_1=2ms^-2
Time of travelt_1=8s
Distance covered=s
Kinematic equations for car 1
s=u_1t_1+1/2a_1t_1^2
Inserting given values we have
s=u_1xx8+1/2xx 2xx8^2
=>s=8u_1+64 .....(1) - Initial velocity
=u_2
Accelerationa_2=9.5ms^-2
Time of travelt_1=4s
Distance covered=s , as both cover the same distance.
Kinematic equations for car 2
s=u_2t_2+1/2a_2t_2^2
Inserting given values we have
s=u_2xx4+1/2xx 9.5xx4^2
=>s=4u_2+76 .......(2)
Equating RHS of (1) with RHS of (2)
Three situations arise:
(a)
We get
From (a) itself we infer that solution exists even if
As such the stated condition which is required to be proved is false.
(b)
From (3) we have
(c)
from equation (3) we have
