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Question #03617

1 Answer

Sep 7, 2016

#((a = -2, b = -7),(a = 0, b = 5))#

Explanation:

Given

#p(x) = (1 + x)^5 (1 + a x)^6 = sum_(k=0)^11 c_kx^k#

we know that

#c_k = (1/(k!)(d^kp)/(dx^k))_(x=0)#

so

#c_1 = 5+6a =b#
#c_2=10 + 30 a + 15 a^2 = 10#

Solving for #a,b# we have two outcomes

#((a = -2, b = -7),(a = 0, b = 5))#

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