Question #bc809

1 Answer
Ratnaker Mehta
Sep 12, 2016

# 3f(2x)=3(8x^2-6x+1)=24x^2-18x+3#.

Explanation:

Given: #f(x) = 2x^2-3x+1#, to find #3f(2x)", or, in fact, "f(2x)#,

what we have to do is : simply replace #x#, in the formula given for

#f(x)#, by #2x#, as shown below :

#f(x) = 2x^2-3x+1 rArr f(2x)=2(2x)^2-3(2x)+1#

#=2(4x^2)-6x+1=8x^2-6x+1#.

#" Therefore, "3f(2x)=3(8x^2-6x+1)=24x^2-18x+3#.

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