Question #3d192

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Question #3d192

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Answer 1 · 2016-09-05T11:30:25

Given a car is driven on a straight line. Its distance $x$ from a traffic light at red, starting point at $t=0$ ; is given as a function of time $t$
$x(t)=2t^2+0.25t^3$

First step: lets find $x(0), x(2) and x(4)$
$x(0)=2xx0^2+0.25xx0^3=0m$
$x(2)=2xx2^2+0.25xx2^3=8+2=10m$
$x(4)=2xx4^2+0.25xx4^3=32+16=48m$
We know that $"Average Velocity"=("Displacement " Delta x)/("Time of travel "Delta t)$
1. $t = 0 s$ to $t = 2 s$
$"Average Velocity"=(x(2)-x(0))/(2-0)=(10-0)/(2)=5ms^-1$
2. $t = 2 s$ to $t = 4 s$
$"Average Velocity"=(x(4)-x(2))/(4-2)=(48-10)/(2)=19ms^-1$
3. $t = 0 s$ to $t = 4 s$
$"Average Velocity"=(x(4)-x(0))/(4-0)=(48-0)/(4)=12ms^-1$

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Question #3d192

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