# Question #1d470

##### 1 Answer

#### Explanation:

All you have to do here is use the **density** of the substance as a **conversion factor** to go from *grams* to *milliliters*.

In essence, this is what the density of a substance is useful for. As you know, density is defined as the **mass** of exactly **one unit of volume** of a substance.

In your case, the density is expressed in *grams per milliliter*, which means that one unit of volume will be

This is what#"3.291 g/mL"# means -- you get#"3.291 g"# for every#"1 mL"# of this substance

You can thus say that

#17 color(red)(cancel(color(black)("g"))) * overbrace("1 mL"/(3.291 color(red)(cancel(color(black)("g")))))^(color(blue)("density as a conversion factor")) = color(green)(|bar(ul(color(white)(a/a)color(black)("5.2 mL")color(white)(a/a)|)))#

The answer is rounded to two **sig figs**.