Question #5bd8d

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Answer 1 · 2016-08-26T14:17:26

We get two pts.

$P_1(1,12/5), and, P_2(-3,16/5)$ satisfying the given cond.

Let the given lines be

$l :x+5y=13, and, l' : 12x-5y+26=0$

Let the reqd. pt. be $P(h,k)$ .

Given $P in l, rArr h+5k=13....................(1)$ .

Also, ( $bot$ )distance from $P$ to $l'$ is $2$ .

$rArr |12h-5k+26|/sqrt(12^2+(-5)^2)=2$

$:. |12h-5k+26|=26, or, 12h-5k+26=+-26$

$:. 12h-5k=0... ...(2'), or, 12h-5k=-52... ...(2'')$

Solving $(1),(2'),(2'')$ , we get two pts.

$P_1(1,12/5), and, P_2(-3,16/5)$ satisfying the given cond.

Enjoy Maths.!