The sum of the squares of three numbers is 116116, and the ratio of these numbers is 2:3:42:3:4. What is the largest number?

2 Answers
Aug 22, 2016

The three numbers are 44, 66 and 88 or -44, -66 and -88.

Hence the largest number is either 88 or -88

Explanation:

If the smallest is 2n2n then the sum of the squares is:

(2n)^2+(3n)^2+(4n)^2 = (2^2+3^2+4^2)n^2 = 29n^2(2n)2+(3n)2+(4n)2=(22+32+42)n2=29n2

Since we are told that this is 116116 we find:

n^2 = 116/29 = 4n2=11629=4

Hence n = +-2n=±2

So the three numbers are 44, 66 and 88 or -44, -66 and -88.

So the largest number is either 88 or -88.

[ Note that the greatest number in the two cases is 88 or -44 ]

Aug 22, 2016

I got 88, assuming positivity. If you wish, you could say that since -2:-3:-4 = 2:3:42:3:4=2:3:4, your highest number is pm8±8, in magnitude.


If you label your unknown variable in lieu of the ratios as xx, then you can have the ratio represented as 2x:3x:4x:2x:3x:4x:.

So, what you have is:

(2x)^2 + (3x)^2 + (4x)^2 = 116(2x)2+(3x)2+(4x)2=116

4x^2 + 9x^2 + 16x^2 = 1164x2+9x2+16x2=116

29x^2 = 11629x2=116

x^2 = 116/29 = 4x2=11629=4

color(blue)(x = pm2)x=±2

Therefore, the largest number is 4x = 4(pm2) = bb(pm8).

To check our work:

2x = 2(pm2) = pm4
3x = 3(pm2) = pm6
4x = 4(pm2) = pm8

Indeed, pm4:pm6:pm8 = pm2:pm3:pm4, and:

(pm4)^2 + (pm6)^2 + (pm8)^2 = 16 + 36 + 64

= 52 + 64 = color(green)(116)