The sum of the squares of three numbers is 116116, and the ratio of these numbers is 2:3:42:3:4. What is the largest number?
2 Answers
The three numbers are
Hence the largest number is either
Explanation:
If the smallest is
(2n)^2+(3n)^2+(4n)^2 = (2^2+3^2+4^2)n^2 = 29n^2(2n)2+(3n)2+(4n)2=(22+32+42)n2=29n2
Since we are told that this is
n^2 = 116/29 = 4n2=11629=4
Hence
So the three numbers are
So the largest number is either
[ Note that the greatest number in the two cases is
I got
If you label your unknown variable in lieu of the ratios as
So, what you have is:
(2x)^2 + (3x)^2 + (4x)^2 = 116(2x)2+(3x)2+(4x)2=116
4x^2 + 9x^2 + 16x^2 = 1164x2+9x2+16x2=116
29x^2 = 11629x2=116
x^2 = 116/29 = 4x2=11629=4
color(blue)(x = pm2)x=±2
Therefore, the largest number is
To check our work:
2x = 2(pm2) = pm4
3x = 3(pm2) = pm6
4x = 4(pm2) = pm8
Indeed,
(pm4)^2 + (pm6)^2 + (pm8)^2 = 16 + 36 + 64
= 52 + 64 = color(green)(116)