If #HO^-=2.7xx10^-11molL^-1#, what is #pOH# of this solution?

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Answer 1 · 2016-08-25T17:42:07

#pOH# #=# #10.57#

#pOH# #=# #-log_10[HO^-]#.

Thus #pOH# #=# #-log_10(2.7xx10^-11)#.

Is this solution acidic or basic? How do you know?

If #HO^-=2.7xx10^-11*mol*L^-1#, what is #pOH# of this solution?