Question #226ac

Question

2567 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-08-19T22:54:37

Given
#n_"Ar"->"No. of moles of Argon"=3" mols"#

#n_"Kr"->"No. of moles of Krypton"=5" mols"#

#p_"Ar"->"Partial pressure of Argon"=210" torr"#

#"Let "p_"Kr"->"Partial pressure of Krypton"=?#

Now In a gas mixture partial pressures of constituent gas is proportional to their respective no. of moles present in the mixture.

So

#p_"Kr"/p_"Ar"=n_"Kr"/n_"Ar"=>p_"Kr"/210=5/3#

#=>p_"Kr"=5/3xx210=350" torr"#

#"Total Pressure"(P)=p_"Kr"+p_"Ar"=(350+210)=560" torr"#