What is pH for a solution whose [H_3O^+]=6.7xx10^-5*mol*L^-1?

1 Answer
anor277
Aug 19, 2016

pH=4.17

Explanation:

pH=log_10[H_3O^+] (equivalently pH=log_10[H^+]).

Thus pH=log_10(6.7xx10^-5) = -(-4.17)

Note that when we write log_ab=c, we are looking for the power to which we raise the base a to get b; here a^c=b. What are log_(10)100, log_(10)1000000, and log_(10)0.001?

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