Question #ee1ea Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer Binayaka C. Aug 19, 2016 In [0< x< 360]; x=150^0,330^0 Explanation: tan(x)=-cot(pi+pi/3) = -cot(180+60)=-cot240=-(1/tan240)=-(1/sqrt3):.x=tan^-1(-1/sqrt3) =-30^0 in [0< x< 360]; x=150^0,330^0 Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for 140^\circ? How do you find the value of cot 300^@? What is the value of sin -45^@? How do you find the trigonometric functions of values that are greater than 360^@? How do you use the reference angles to find sin210cos330-tan 135? How do you know if sin 30 = sin 150? How do you show that (costheta)(sectheta) = 1 if theta=pi/4? See all questions in Trigonometric Functions of Any Angle Impact of this question 1251 views around the world You can reuse this answer Creative Commons License