Question #d2529

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Question #d2529

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Answer 1 · 2016-08-16T20:38:04

$\sqrt[4]{16 x^{4} y^{5}} \cdot \sqrt[4]{243 y^{7}} = 6 x y^{3} \sqrt[4]{3}$ $root(4)(16x^4y^5)*root(4)(243y^7)=6xy^3 root(4)3$

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$\sqrt[4]{16 x^{4} y^{5}} \cdot \sqrt[4]{243 y^{7}} ?$ $root(4)(16x^4y^5)*root(4)(243y^7) ?$

$\sqrt[4]{2^{4} x^{4} y^{12} \cdot 3^{4} \cdot 3^{1}} = 2 \cdot 3 \cdot x \cdot y^{3} \sqrt[4]{3} = 6 x y^{3} \sqrt[4]{3}$ $root(4)(2^4x^4y^12*3^4*3^1)=2*3*x*y^3root(4)3=6xy^3 root(4)3$

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