What quantity of water results from the combustion of a #0.5*g# mass of dihydrogen gas?

1 Answer
anor277
Aug 15, 2016

Approx, #4.25*g#.

Explanation:

First, we need a stoichiometrically balanced equation, i.e.

#H_2(g) + 1/2O_2(g) rarr H_2O(g)+Delta#

#"Moles of dihydrogen"# #=# #(0.5*g)/(2xx1.00794*g*mol^-1)=0.25*mol#

Given the #1:1# stoichiometry, if #0.25*mol# dihydrogen react, then #0.25*mol# water result.

#"Mass of water"# #=# #0.25*cancel(mol)xx18.02*g*cancel(mol^-1)=??g#

How many grams of dioxygen were involved?

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