How do you simplify #((2i)/(1+i))^2# ?
1 Answer
Aug 14, 2016
#((2i)/(1+i))^2 = 2i#
Explanation:
#((2i)/(1+i))^2 = ((2i)^2)/(1+i)^2=(2^2i^2)/(1+2i+i^2)=(-4)/(2i)#
#=(-2)/i=(-2i)/i^2=(-2i)/(-1)=2i#
