Question #df20b

Question

1297 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-12-28T11:57:24

Here initial vlocity of the truck is $u =159.2 "km/hr"=(159.2xx10^3)/3600m/s$

Final velocity of the truck $v=0$

The truck retards uniformly during skidding to come to a stop.

The time of skidding $t=5.85s$
So distance of skiding

$s=1/2(u+v)xxt$

$=>s=1/2((159.2xx10^3)/3600+0)xx5.85$

$=>s=129.35m$