Question #d665b Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Ratnaker Mehta Aug 3, 2016 #x=(3n+1)pi/9-2/3, n in ZZ#. Explanation: We will use : The Soln. Set of the eqn. # : tantheta=tanalpha# is #theta in {npi+alpha, n in ZZ}#. Since, #tan(3x+2)=sqrt3=tan(pi/3)#, we have, #(3x+2)=npi+pi/3=(3n+1)pi/3 rArr 3x=(3n+1)pi/3-2# #:. x=(3n+1)pi/9-2/3, n in ZZ#. Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 816 views around the world You can reuse this answer Creative Commons License