Question #d665b

1 Answer
Ratnaker Mehta
Aug 3, 2016

x=(3n+1)pi/9-2/3, n in ZZ.

Explanation:

We will use :

The Soln. Set of the eqn. : tantheta=tanalpha is theta in {npi+alpha, n in ZZ}.

Since, tan(3x+2)=sqrt3=tan(pi/3), we have,

(3x+2)=npi+pi/3=(3n+1)pi/3 rArr 3x=(3n+1)pi/3-2

:. x=(3n+1)pi/9-2/3, n in ZZ.

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