Question #de7ca

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Answer 1 · 2016-12-01T05:38:25

We know that the distance traveled by the body in *n th sec is given by the equation

#S_n=u+1/2a(2n-1)#

where u is the initial velocity and a is the uniform acceleration of the body.

In our given problem #u=0#

So distance traveled in 3rd sec

#S_3=1/2a(2*3-1)=5/2a#

And distance traveled in 4th sec

#S_4=1/2a(2*4-1)=7/2a#

So the ratio of distance traveled is

#S_3/S_4=5/7#