Question #3365f

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Question #3365f

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Answer 1 · 2016-09-02T11:38:34

The required angle is #59.04^0(2dp)#

Explanation:

Let "p" be height where ladder rests on wall and "b" be the base distance of the ladder from wall at ground, then #tan theta=p/b=50/30=5/3:.theta=tan^-1(5/3)=59.04^0(2dp)#[Ans]

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Question #3365f

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