Question #b3c29

4 Answers
Jan 4, 2016

""_13Al:1s^(2)2s^(2)2p^(6)3s^(2)3p^113Al:1s22s22p63s23p1

Explanation:

The electron configuration of Aluminum is:

""_13Al:1s^(2)2s^(2)2p^(6)3s^(2)3p^113Al:1s22s22p63s23p1

Jul 4, 2016

[Ne]3s^2 3p^1[Ne]3s23p1

Explanation:

Atomic number is 13. The last noble gas with atomic number below 13 is Neon (atomic number 10).

Configuration of Neon is 1s^2 2s^2 2p^61s22s22p6 so this leaves 3 more electrons for Aluminium. Two electrons will go into the 3s, and the remaining one into the 3p.

Jul 4, 2016

[Ne] 3s^2 3p^1[Ne]3s23p1

Explanation:

The electron configuration for Aluminum is

1s^2 2s^2 2p^6 3s^2 3p^11s22s22p63s23p1

Aluminum is found in the 3rd3rd energy level 1st1st column of the pp block.

The short hand or noble gas notation for this would use

[Ne] 3s^2 3p^1[Ne]3s23p1

The [Ne][Ne] represents 1s^2 2s^2 2p^61s22s22p6

Jul 25, 2016

"Al: " 1s^2 2s^2 2p^6 3s^2 3p^1Al: 1s22s22p63s23p1

Explanation:

For starters, grab a periodic table and look for aluminium, "Al"Al. You'll find it listed in period 3, group 13. Notice that the element has an atomic number equal to 1313.

This tells you that a neutral aluminium atom contains 1313 protons inside its nucleus and 1313 electrons surrounding its nucleus. You can thus say that the electron configuration for aluminium must account for a total of 1313 electrons.

As you know, electron configurations are written in accordance with the Aufbau Principle. The available empty orbitals in order of increasing energy look like this

http://www.chemguide.co.uk/atoms/properties/atomorbs.htmlhttp://www.chemguide.co.uk/atoms/properties/atomorbs.html

Your goal now will be to start adding electrons to these orbitals. The first energy level contains a single orbital, so the first two electrons go in the 1s1s orbital

"Al: " color(blue)(1s^2)Al: 1s2

You're now down to 1111 electrons. The second energy level contains a total of 44 orbitals. The first orbital to be filled on this energy level is the 2s2s orbital

"Al: " color(blue)(1s^2) color(red)(2s^2)Al: 1s22s2

You're down to 99 electrons. The next 66 electrons are distributed in the 2p2p orbitals

"Al: " color(blue)(1s^2) color(red)(2s^2 2p^6)Al: 1s22s22p6

You're down to 33 electrons. The first orbital to be filled on the third energy level is the 3s3s orbital

"Al: " color(blue)(1s^2) color(red)(2s^2 2p^6) color(green)(3s^2)Al: 1s22s22p63s2

Finally, the last electron is added to one of the 3p3p orbitals

color(green)(|bar(ul(color(white)(a/a)color(black)("Al: " 1s^2 2s^2 2p^6 3s^2 3p^1)color(white)(a/a)|)))

And there you have it, the complete electron configuration for aluminium.