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Question #98a20

1 Answer

Aug 29, 2016

# sin (15^@20')=cos (74^@40')#.

Explanation:

We know that, #sin theta=cos (90^@- theta)#

#:. sin (15^@20')=cos (90^@-15^@20')#

Recall that, #1^@=60'#, so, we can say that, #90^@=89^@60'#.

#:. (90^@-15^@20')=(89^@60'-15^@20')#

#=74^@40'#

Therefore, # sin (15^@20')=cos (74^@40')#.

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