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Question #7ef19

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Oct 15, 2016

For the given figure

#"In" DeltaBCE and DeltaADE, /_BEC=/_AED->"Vertically opposite"#

Again #(BE)/(DE)=(CE)/(AE)=1/3#

#"So" DeltaBCE and DeltaADE->Similar#

Hence # (BC)/(AD)=(BE)/(DE)=(CE)/(AE)=1/3#

# =>(BC)/(AD)=1/3#

# =>6/(AD)=1/3#

#=>AD=18cm#

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