How many valence electrons are present in 40*g40⋅g mass of calcium metal?

1 Answer
anor277
Jul 14, 2017

There are approx. 2xxN_A2×NA valence electrons, where N_A-="Avogadro's number"NA≡Avogadro's number..........

Explanation:

Each calcium atom has 2 valence electrons, and calcium commonly forms a Ca^(2+)Ca2+ ion..........

Now the molar mass of calcium is 40.1*g*mol^-140.1⋅g⋅mol−1, and thus a 40 gram quantity of calcium metal CONTAINS 6.022xx10^236.022×1023 individual calcium atoms. Note that this is the principle of chemical equivalence. If you gots the mass of something, you know the number of fundamental particles of stuff that make up that something.

And so we gots 12.022xx10^2312.022×1023 individual electrons.........

Related questions
See all questions in Valence Electrons
Impact of this question
6956 views around the world
You can reuse this answer
Creative Commons License