Question #92b48

1 Answer
Jul 8, 2016

~~0.26

Explanation:

Let in the mixture

"No. of moles of " ""^10B=x " mol"

"No. of moles of " ""^11B=y " mol"

:. "Mole fraction of "^10B=x/(x+y)

So

x xx 10.012+ yxx11.093=(x+y)xx10.811

=> yxx11.093-yxx10.811=x xx10.811-x xx 10.012

=>0.282y=0.799x

=>y/x=799/282

=>y/x+1=799/282+1

=>(x+y)/x=(282+799)/282=1081/282

=>x/(x+y)=282/1081~~0.26

:. "Mole fraction of "^10B=x/(x+y)=282/1081~~0.26