Question #863c8
1 Answer
Hydrogen peroxide is the oxidizing agent and lead(II) sulfite is the reducing agent.
Explanation:
Lead(II) sulfite,
In this reaction, the lead(II) sulfite will be oxidized to lead(II) sulfate and the hydrogen peroxide will be reduced to water.
You can thus say that thee hydrogen peroxide acts as an oxidizing agent because it oxidizes lead(II) sulfite to lead(II) sulfate.
Similarly, the lead(II) sulfite acts as a reducing agent because it reduces the hydrogen peroxide to water.
The balanced chemical equation that describes this redox reaction looks like this
#stackrel(color(blue)(+2))("Pb") stackrel(color(blue)(-2))("S")_ ((s)) + 4 stackrel(color(blue)(+1))("H")_ 2 stackrel(color(blue)(-1))("O")_ (2(aq)) -> stackrel(color(blue)(+2))("Pb") stackrel(color(blue)(+6))("S") stackrel(color(blue)(-2))("O")_ (4(aq)) + 4 stackrel(color(blue)(+1))("H")_ 2 stackrel(color(blue)(-2))("O")_ ((l)) #
Notice that the oxidation state of oxygen goes from
On the other hand, the oxidation state of sulfur is going from
Therefore, you have
#color(white)(a)"PbS" -> # reducing agent
#"H"_2"O"_2 -># oxidizing agent