Question #5c707

1 Answer
Jul 5, 2016

Here's how you can do that.

Explanation:

Ammonium phosphate, ("NH"_color(red)(4))_color(blue)(3)"PO"_4(NH4)3PO4, is an ionic compound made up of ammonium cations, "NH"_4^(+)NH+4, and phosphate anions, "PO"_4^(3-)PO34.

As you can see from the compound's chemical formula, one formula unit of ammonium phosphate contains

  • three ammonium cations, color(blue)(3) xx "NH"_4^(+)3×NH+4
  • one phosphate anion, 1 xx "PO"_4^(3-)1×PO34

http://www.wikiwand.com/en/Ammonium_phosphate

This of course means that one mole of ammonium phosphate will contain color(blue)(3)3 moles of ammonium cations and 11 mole of phosphate anions.

Now, each ammonium cation is made up of

  • one atom of nitrogen, 1 xx "N"1×N
  • four atoms of hydrogen, color(red)(4) xx "H"4×H

Since one mole of ammonium cations will contain color(red)(4)4 moles of hydrogen atoms, it follows that one mole of ammonium phosphate will contain a total of

color(blue)(3) color(darkred)(cancel(color(black)("moles NH"_4^(+)))) * (color(red)(4)color(white)(a)"moles of H")/(1color(darkred)(cancel(color(black)("mole NH"_4^(+))))) = color(green)(|bar(ul(color(white)(a/a)color(black)("12 moles of H")color(white)(a/a)|)))

Therefore, you can say that every mole of ammonium phosphate contains a total of 12 moles of hydrogen atoms.

You can expand this to say that for any number of moles of ammonium chloride given to you, n, the number of moles of hydrogen atoms can be found by multiplying n by 12

n color(red)(cancel(color(black)("moles"color(white)(a)("NH"_4)_3"PO"_4))) * "12 moles H"/(1color(red)(cancel(color(black)("mole"color(white)(a)("NH"_4)_3"PO"_4)))) = (12 * n)color(white)(a)"moles H"