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Question #e9bd2

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Jul 1, 2016

#/_CDO=35^o#.

Explanation:

The diagonals [ #AC# & #BD# ] of rhombus [ #ABCD# ] intersect [ at #O# ] at Right Angles.

Now consider #DeltaAOB#, in which, #(1)/_AOB=90^o, (2) /_OAB=55^o [ Given ]#, giving #(3)/_OBA=35^o#

Notice that, #DC || AB#, & #DB# is a transvers, making congruent pair of angles #/_CDB# and #/_DBA.#

#:.# Reqd. Angle = #/_CDO#=#/_CDB#=#/_DBA#=#/_OBA=35^o,# using #(3)#.

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