Question #78370

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Answer 1 · 2016-06-17T16:24:17

Probability is $=0.0612$

Given -

Electrical Engineers = 40
Chemical Engineers =20
Mechanical Engineers = 30
Civil Engineers = 10

Total Engineers = 100

In how many ways 4 engineers are selected from
100 engineers $=_100CC_4=3921225$

How may ways one Electrical Engineer is selected from 40 $=_40CC_1=40$

How may ways one Chemical Engineer is selected from 20 $=_20CC_1=20$

How may ways one Mechanical Engineer is selected from 30 $=_30CC_1=30$

How may ways one Civil Engineer is selected from 10 $=_10CC_1=10$

Probability of One Electrical and One Chemical and One Mechanical and One Civil Engineers $=(40xx20xx30xx10)/3921225=240000/3921225=0.0612$