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How much oxygen gas can I make from a #9*kg# mass of water?

1 Answer

Jun 17, 2016

#H_2O(g) rarr 1/2O_2(g) + H_2(g)#

Explanation:

You have #90xx10^3*g# of water. This represents a MOLAR quantity of #(90xx10^3*g)/(18*g*mol^-1)=??mol#.

The number of moles of oxygen gas, #O_2#, is half this molar quantity by the stoichiometric equation.

And of course each mole of oxygen gas has a mass of #32*g#. From where am I getting these masses? Do you have to learn them?

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