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Answer 1 · 2017-12-31T18:10:32

If you specified the data related to enthalpy and entropy, we could calculate the free energy change via,

$DeltaG = DeltaH^° - TDeltaS$

But you want to make it hard for me! Let's calculate the enthalpy and entropy of the reaction you specified,

$N_2O_4(g) to 2NO_2(g)$ , where

$DeltaH° = 58kJ$

$DeltaS = (176J)/K$

assuming that dinitrogen tetroxide is a gas.

Hence,

$DeltaG° = 58*10^3 J - 298K * (176J)/K$
$therefore DeltaG° = 5.6kJ$