Question #9416d

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Question #9416d

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Answer 1 · 2016-09-27T15:24:37

We know that the values of $f (x)$ $f(x)$ are real numbers for
$f (x) = {log}_{a} (x - k)$ $f(x) = Log_a ( x - k)$ where $k$ $k$ constant, if argument of $log$ $log$ is positive.
$(x - k) > 0$ $(x-k)>0$
$\Rightarrow x > k$ $=>x>k$

Inserting given numbers we get domain of
$log (x - 7)$ $log(x-7)$ in inequality form as
$x > 7$ $x>7$
In interval form as
$(7, + \infty)$ $(7 , + oo)$

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Question #9416d

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