What mass of magnesium chloride is associated with $2.29xx10^23$ formula units of magnesium chloride?

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Answer 1 · 2016-06-06T19:46:10

Avogadro's number of $"magnesium chloride fomula units"$ have a mass of $95.21*g$ . So you have a mass of approx. $40*g$ .

$(2.29xx10^23" magnesium chloride formula units")/(6.022xx10^23" magnesium chloride formula units per mole")$ $xx$ $95.21*g*mol^-1$ $=$ $??g$

What mass of magnesium chloride is associated with 2.29xx10^232.29xx10^23 formula units of magnesium chloride?