Question #8c852

To solve this problem, you must find a conversion factor that can take you from moles of silver to grams of silver.

To find that conversion factor, grab a periodic table and look for silver, #"Ag"#. You'll find the element in period 5, group 11.

Your conversion factor is called molar mass and is located at the bottom of the block.

The molar mass of an element tells you how the mass of exactly one mole of that element. In your case, silver is said to have a molar mass of #"107.868 g mol"^(-1)#.

This tells you that every mole of silver has a mass of #"107.868 g"#. If that is the case, then #7.52# moles will have a mass of

#7.52 color(red)(cancel(color(black)("moles Ag"))) * overbrace("107.868 g"/(1color(red)(cancel(color(black)("mole Ag")))))^(color(purple)("molar mass of silver")) = "811.17 g"#

You need to round this off to three sig figs, the number of sig figs you have for the number of moles of silver

#"mass of silver" = color(green)(|bar(ul(color(white)(a/a)"811 g"color(white)(a/a)|)))#

Therefore, #"811 g"# of silver will contain #7.52# moles of silver.