Question #9e62c

2 Answers
anor277
May 15, 2016

For acetic acid, #H_3C-C(=O)OH#?

Explanation:

#H_3C-C(=O)OH(aq) + H_2O rightleftharpoons H_3C-C(=O)O^(-) + H_3O^+#

#K_a = ([H_3O^+][H_3C-C(=O)O^-])/([H_3C-C(=O)OH(aq)])#

#K_a = 10^(-4.76)#

SCooke
May 15, 2016

Acetic acid has one ionization to the hydrogen ion and the acetate ion:
#H_3CCOOH ↔ H_3CCOO^-# + #H^+#

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