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Question #69fd6

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BRIAN M. · Oscar L.

May 12, 2016

#[H_3O^+] = 2.24\times10^-5#

Explanation:

Take the antilog of the negative pH to find the #[H_3O^+]# concentration

antilog#[-4.65] =#

#10^[-4.65] =#

#[H_3O^+] = 2.24\times10^-5#

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