What molar quantity of the metal salt are present in a #0.667*g# mass of sodium dichromate?

1 Answer
anor277
May 11, 2016

#"5.10 mmol"#

Explanation:

#"Moles of sodium dichromate" = (0.667*g)/(261.97*g*mol )=2.55xx10^-3 *mol#.

Given the composition of sodium dichromate, #Na_2Cr_2O_7#, there are twice this molar quantity of sodium ions. How many oxygen atoms?

Related questions
See all questions in The Mole
Impact of this question
1707 views around the world
You can reuse this answer
Creative Commons License