What are the nodal planes of the $d_{x^{2} - y^{2}}^{2}$ $d_(x^2-y^2)$ orbital?

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What are the nodal planes of the $d_{x^{2} - y^{2}}^{2}$ $d_(x^2-y^2)$ orbital?

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Answer 1 · 2016-06-29T04:30:03

The nodal planes of the $d_{x^{2} - y^{2}}^{2}$ $d_(x^2-y^2)$ orbitals are the non-axial planes.

Explanation:

A nodal plane or nodal surface of a wave-function is an area where there is zero displacement; zero electron density.

Example: $3 d_{x^{2} - y^{2}}^{2}$ $3d_(x^2-y^2)$ orbital

![ www.chemguide.co.uk )

Since the $d - orbitals$ $d-"orbitals"$ have definite geometric properties, it is easy to recognize such planes/surfaces, and these are the regions which have no axial component in the $x y$ $xy$ plane.

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What are the nodal planes of the $d_{x^{2} - y^{2}}^{2}$ $d_(x^2-y^2)$ orbital?

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Explanation:

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What are the nodal planes of the $d_{x^{2} - y^{2}}^{2}$ $d_(x^2-y^2)$ orbital?