Question #0ac36

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Answer 1 · 2018-01-05T16:06:18

We know that $1" amu"=1.6606xx10^-27" kg"$
Velocity of light $c$ in vacuum is $=2.9979xx10^8" ms"^-1$

Using the Einstein's mass equivalence relation we get energy equivalent of

$1" amu"=931.5" MeV"$

Now mass of $1$ proton $=1.007276471" amu"$
$:.$ mass of $2$ proton $=1.007276471xx2" amu"$

Energy equivalent of $2$ protons $=1.007276471xx2xx931.5xx10^6$

$=1.88xx10^9" eV"$

We know that $1" eV"=1.60218xx10^-19" J"$
$:.$ Energy equivalent of $2$ protons $=1.88xx10^9xx1.60218xx10^-19$

$=3.0xx10^-10" J"$