Question #68f30
1 Answer
Explanation:
That is
sin((2pi)/3+(5pi)/4) = sin((2pi)/3)cos((5pi)/4) + cos((2pi)/3)sin((5pi)/4)sin(2π3+5π4)=sin(2π3)cos(5π4)+cos(2π3)sin(5π4)
= sqrt3/2 (-sqrt2/2) + (-1/2)(-sqrt2/2)=√32(−√22)+(−12)(−√22)
= (sqrt2 - sqrt6)/4=√2−√64
thus
csc((2pi)/3+(5pi)/4) = 4/(sqrt2 - sqrt6) = -4 * (sqrt2 + sqrt6)/4 = -sqrt2 - sqrt6csc(2π3+5π4)=4√2−√6=−4⋅√2+√64=−√2−√6
Note