Question #f8288

1 Answer
A08
Apr 27, 2016

#3.0xx10^4 " miles" " hour"^-2#

Explanation:

Let us use the expression between velocity, time #t# and acceleration #a#, assuming a constant force is applied during the interval.

#v=u+at#
where #v# is final velocity and #u# is initial velocity of car. Substituting given values

#60=0+axx7.2/3600#, seconds to be converted to hours. Solving for #a#
#a=60xx3600/7.2=30000#
#=3.0xx10^4 " miles" " hour"^-2#

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