Question #f8288

1 Answer
A08
Apr 27, 2016

3.0xx10^4 " miles" " hour"^-2

Explanation:

Let us use the expression between velocity, time t and acceleration a, assuming a constant force is applied during the interval.

v=u+at
where v is final velocity and u is initial velocity of car. Substituting given values

60=0+axx7.2/3600, seconds to be converted to hours. Solving for a
a=60xx3600/7.2=30000
=3.0xx10^4 " miles" " hour"^-2

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