Question #b0676

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Question #b0676

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Answer 1 · 2016-04-23T14:55:10

LHS
#=sin(x+y)sin(x-y)#
#=(sinxcosy+cosxsiny)*(sinxcosy-cosxsiny)#
#=(sin^2xcos^2y-cos^2xsin^2y)#
#=(sin^2x(1-sin^2y)-(1-sin^2x)sin^2y)#
#=(sin^2x-cancel(sin^2x*sin^2y)-sin^2y+cancel(sin^2xsin^2y))#
#=(sin^2x-sin^2y)#=RHS

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Question #b0676

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