Question #85638

1 Answer
A. S. Adikesavan
Apr 29, 2016

#x =-(log 3 - log 2 )/log 3=-0.3691#, nearly.

Explanation:

Use# (ab)^n=a^nb^n, a^(m+n)=a^ma^n and log(a^n)=n log a#

#((3)(2))^(x+1)=3^(x+1)2^(x+1)=2^(x+2)#.

So, #3^(x+1)=2#.

Equating logarithms and simplifying,

#x =-(log 3 - log 2 )/log 3=-0.3691#, nearly.

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