What would the concentration of hydroxide anions be in an aqueous solution that has #["H"_3"O"^(+)] = "0.325 M"# ? Given: #K_w = 10^(-14)# #"mol"^2"L"^2#

1 Answer
Michael
Apr 21, 2016

#3.08xx10^(-14)" ""mol""/""l"#

Explanation:

At #25^@"C"# the ionic product of water is given by:

#K_w=[H_3O_((aq))^(+)][OH_((aq))^(-)]=10^(-14)" ""mol"^(2)."l"^(-2)#

#:.[OH_((aq))^(-)]=K_w/[[H_3O_((aq))^(+)]]#

#[OH_((aq))^(-)]=10^(-14)/0.325=3.08xx10^(-14)" ""mol""/""l"#

Related questions
See all questions in pH
Impact of this question
1698 views around the world
You can reuse this answer
Creative Commons License