What is the conjugate base of oxalic acid, #HO(O=)C-C(=O)OH#?

2 Answers
anor277
May 4, 2016

The conjugate base of oxalic acid is #HO(O=)C-C(=O)O^-#

Explanation:

The conjugate base of any acid, #HA#, is the original acid LESS a proton, #H^+#. As for any chemical reaction, mass and charge are conserved. Therefore the conjugate base of #HA# is #A^-#.

Here we start with a (potential) diacid, #HO(O=)C-C(=O)OH#, oxalic acid. So we remove a proton, and get #HO(O=)C-C(=O)O^-#. The conjugate base of this species is #""^(-)O(O=)C-C(=O)O^-#, oxalate anion.

P dilip_k
May 4, 2016

#HOOC.COO^-#

Explanation:

If it represnts the molecular formula of oxalic acld #HOOC .COOH#.Its conjugate base is the anion formed due to release of proton #H^+#.
So the conjugate base is #HOOC.COO^-#

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