What is the conjugate base of oxalic acid, HO(O=)C-C(=O)OH?

2 Answers
anor277
May 4, 2016

The conjugate base of oxalic acid is HO(O=)C-C(=O)O^-

Explanation:

The conjugate base of any acid, HA, is the original acid LESS a proton, H^+. As for any chemical reaction, mass and charge are conserved. Therefore the conjugate base of HA is A^-.

Here we start with a (potential) diacid, HO(O=)C-C(=O)OH, oxalic acid. So we remove a proton, and get HO(O=)C-C(=O)O^-. The conjugate base of this species is ""^(-)O(O=)C-C(=O)O^-, oxalate anion.

P dilip_k
May 4, 2016

HOOC.COO^-

Explanation:

If it represnts the molecular formula of oxalic acld HOOC .COOH.Its conjugate base is the anion formed due to release of proton H^+.
So the conjugate base is HOOC.COO^-

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