Question #bd857

1 Answer
Apr 5, 2016

#3.58\times10^{23}# molecules of oxygen will be formed.

Explanation:

The molecular weight of #KClO_3# (one atom of potassium + one of chlorine + three of oxygen) is 122.55 g/mol. So 48.5 g of #KClO_3# is 48.5/122.55=0.396 mol.

The balanced equation shows we have 3 moles of oxygen for every 2 moles of #KClO_3#. So the 0.396 mol of #KClO_3# will make 0.594 mol of oxygen. Each mole has #6.02\times10^{23}# molecules, and #0.594\times6.02\times10^{23}=3.58\times10^{23}#.