Question #bcca3

Question

2162 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-08-31T16:28:26

Period is dependent on the angular frequency which depends on the physical configuration of the Oscillator.

For a spring oscillator were the particle has mass $m$ and spring has force constant $k$ , then

$omega = sqrt(k/m)$

And the time period, $T = (2pi)/omega$

Also for a pendulum of length $l$ undergoing simple harmonic motion,

$omega = sqrt(g/l)$ represents the angular frequency. And time period is determined from the same relation as before.

The amplitude however, is an arbitrary constant and doesn't quite depend on $k$ or $l$ .