Question #19ce3

1 Answer
Mar 24, 2016

#"37.8 L"#

Explanation:

Your strategey here will be to

  • use the molar mass of the gas to convert the sample to moles

  • use the molar volume of a gas a STP as a conversion factor

The molar volume of a gas at STP can be used as a conversion factor that helps you go from moles to liters, or vice versa.

As its name suggest, the molar volume of a gas at STP will tell you what volume would one mole of a gas occupy under STP conditions.

Now, STP conditions are currently defined as a pressure of #"100 kPa"# and a temperature of #0^@"C"#. Under these conditions for pressure and temperature, one mole of any ideal gas occupies #"22.7 L"#.

In other words, a gas kept under STP conditions will have a molar volume of #"22.7 L mol"^(-1)#.

In your case, the problem provides you with the mass of neon, which means that you're going to have to use its molar mass to convert it to moles.

#33.6 color(red)(cancel(color(black)("g"))) * overbrace("1 mole Ne"/(20.18color(red)(cancel(color(black)("g")))))^(color(brown)("molar mass of Ne")) = "1.665 moles Ne"#

So, if one mole occupies #"22.7 L"# at STP, it follows that this many moles will occupy

#1.665color(red)(cancel(color(black)("moles Ne"))) * overbrace("22.7 L"/(1color(red)(cancel(color(black)("mole Ne")))))^(color(purple)("molar volume of a gas at STP")) = color(green)(|bar(ul(color(white)(a/a)"37.8 L"color(white)(a/a)|)))#

The answer is rounded to three sig figs.

SIDE NOTE Many sources still use the old definition of STP, which implies a pressure of #"1 atm"# and a temperature of #0^@"C"#.

Under these conditions, one mole of any ideal gas occupies #"22.4 L"#.

If this is the value given to you for the molar volume of a as at STP, simply redo the calculations using #"22.4 L"# instead of #"22.7 L"#.