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Question #8ed5a

1 Answer

May 30, 2016

$(df)/(dx)(x) = sum_{i=1}^n (n-i)a^i x^{n-i-1}$

Explanation:

$f(x) = sum_{i=0}^n a^i x^{n-i}$
so deriving
$(df)/(dx)(x) = sum_{i=1}^n (n-i)a^i x^{n-i-1}$

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