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Question #8ed5a

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May 30, 2016

#(df)/(dx)(x) = sum_{i=1}^n (n-i)a^i x^{n-i-1}#

Explanation:

#f(x) = sum_{i=0}^n a^i x^{n-i}#
so deriving
#(df)/(dx)(x) = sum_{i=1}^n (n-i)a^i x^{n-i-1}#

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